Question

The major organic product in the reaction is \[\mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}(\mathrm{CH}_{3})_{2}+\mathrm{HI}\to\mathrm{products}\]:

विकल्प

• \[\mathrm{CH}_3\mathrm{I}+(\mathrm{CH}_3)_2\mathrm{CHOH}\]

• \[\mathrm{CH}_3\mathrm{OH}+(\mathrm{CH}_3)_2\mathrm{CHI}\]

• \[\mathrm{ICH}_2\mathrm{OCH}(\mathrm{CH}_3)_2\]

• \[\begin{array} {c}\mathrm{CH}_3\mathrm{OC}(\mathrm{CH}_3)_2 \\ | \\ \mathrm{I} \end{array}\]

Answer 1

\[\mathrm{CH}_3\mathrm{I}+(\mathrm{CH}_3)_2\mathrm{CHOH}\]

Explanation:

In case of unsymmetric ethers when treated with HI then I- attaches to smaller and less complex alkyl group as it follows S_N² mechanism.

\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{............}|\\
\phantom{}\ce{CH3-O-CH} \\
\phantom{...........}|\\\phantom{...............}\ce{CH3}\\
\end{array}\]\[\begin{array}{cc}
\phantom{}\ce{+HI ->(CH3)2CHOH} \\
\end{array}\]