Advertisements
Advertisements
प्रश्न
The magnification by a lens is -3. Name the lens and state how are u and v related?
Advertisements
उत्तर
The negative value of magnification suggests that image is real and inverted. The magnitude of magnification is greater than 1 which means image is enlarged. Therefore the lens should be convex lens.
Relation between u and v is given by
m = `"v"/"u"`
`-3 = "v"/-"u"`
v = 3 u
This shows that image distance is 3 times that of object distance.
संबंधित प्रश्न
The following diagram shows an object AB and a converging lens L with foci F1 and F2. Draw two rays from the object AB and complete the diagram to locate the position of the image CD. Also mark on the diagram the position of eye from where the image can be viewed.
A lens forms an erect, magnified, and virtual image of an object. Where is the object placed in relation to the lens?
A lens forms an erect, magnified and virtual image of an object.Draw a ray diagram to show the formation of image.
A lens forms an erect, magnified, and virtual image of an object. Name the device which uses this principle.
If the magnification produced by a lens is - 0.5, the correct statement is ______.
An object is placed at a distance of 20 cm in front of a concave lens of focal length 20 cm. find: the magnification of image.
Name the lens for which magnification can be 1. For what position of the object will the magnification be 1?
An object is placed in front of a lens between its optical centre and the focus and forms a virtual, erect, and diminished image. Draw a ray diagram to show the formation of the image with the above-stated characteristics.
Copy and complete the following ray diagram.
An erect, magnified, and a virtual image is formed when an object is placed between the optical centre and principal focus of a lens.
(i) Name the lens.
(ii) Draw a ray diagram to show the formation of the image with the above-stated characteristics.
