Question

The magnetic dipole moment of a coil of N turns, carrying current I and enclosing area A, is:

विकल्प

• \[m = NIAB\sin\theta\]

• \[m = \frac{NI}{A}\]

• \[m = \frac{NIB}{A}\]

• \[m = NIA\]

Answer 1

The magnetic dipole moment of a coil is \[m = NIA\], where N is the number of turns, I the current, and A the area of the loop. In vector form it is written as \[\vec{m} = NI\vec{A}\].