हिंदी

The length of DC is ______.

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प्रश्न

The length of DC is ______.

The image displays a geometric problem setup featuring two right-angled triangles sharing a vertical height at vertex $B$, with a right angle at vertex $B$, an angle of elevation of $45^{\circ}$ at vertex $C$, an angle of elevation of $30^{\circ}$ at vertex $D$, and a horizontal base segment $CB$ of length $45\text{ m}$.

विकल्प

  • \(45 \sqrt{3} \mathrm{~m}\)

  • \((45-\sqrt{3}) \mathrm{m}\)

  • \(45(\sqrt{3}-1) \mathrm{m}\)

  • \(45(\sqrt{3}+1) \mathrm{m}\)

MCQ
रिक्त स्थान भरें
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उत्तर

The length of DC is \(\underline{\boldsymbol{45(\sqrt{3}-1) \mathrm{m}}}\).

Explanation:

We know that,

\[\tan \theta = \frac{\text{Perpendicular}}{\text{Base}}\]

From figure,

In △ ABC,

\[\Rightarrow \tan 45^\circ = \frac{AB}{BC}\]

\[\Rightarrow 1 = \frac{AB}{45}\]

⇒ AB = 45 m.

In △ ABD,

\[\Rightarrow \tan 30^\circ = \frac{AB}{BD}\]

\[\Rightarrow \frac{1}{\sqrt{3}} = \frac{45}{BD}\]

\[\Rightarrow BD = 45\sqrt{3}\ \text{m}.\]

From figure,

DC = BD − BC = \[45\sqrt{3} - 45 = 45(\sqrt{3} - 1)\ \text{m}.\]

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अध्याय 22: Height and Distances - TEST YOURSELF [पृष्ठ ३५३]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 22 Height and Distances
TEST YOURSELF | Q 1. (e) | पृष्ठ ३५३
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