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प्रश्न
The least value of f(x) = x3 − 12x, ∈ [0, 3] is ______.
विकल्प
−16
−9
0
16
MCQ
रिक्त स्थान भरें
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उत्तर
The least value of f(x) = x3 − 12x, ∈ [0, 3] is −16.
Explanation:
Given f(x) = x3 − 12x on [0, 3].
Differentiate: f′(x) = 3x2 − 12 = 0 ⇒ x = 2
Check values: f(0) = 0, f(2) = −16, f(3) = −9
Thus, the least value in the interval is −16 at x = 2.
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