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प्रश्न
The joint equation of pair of straight lines passing through the origin and having slopes `1 + sqrt2` and `1/(1 + sqrt2)` is ______
विकल्प
x2 + 2xy + y2 = 0
x2 + 2xy - y2 = 0
`x^2 - 2sqrt2 xy + y^2 = 0`
`x^2 - 2sqrt2 xy - y^2 = 0`
MCQ
रिक्त स्थान भरें
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उत्तर
The joint equation of pair of straight lines passing through the origin and having slopes `1 + sqrt2` and `1/(1 + sqrt2)` is `underline(x^2 - 2sqrt2 xy + y^2 = 0)`.
Explanation:
Joint equation of pair of lines having slopes m1 and m2 and passing through the origin is `y^2 - (m_1 + m_2)xy + m_1m_2x^2 = 0`
⇒ `y^2 - (1 + sqrt2 + 1/(1 + sqrt2))xy + (1 + sqrt2)(1/(1 + sqrt2)) x^2 = 0`
⇒ `y^2 - (1 + sqrt2 + (sqrt2 - 1)/1)xy + x^2 = 0`
⇒ `x^2 - 2sqrt2xy + y^2 = 0`
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Shift of Origin
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