हिंदी

The ionic radii of A+ and B− are 0.98 × 10−10 m and 1.81 × 10−10 m. The coordination number of each ion in AB is ______.

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प्रश्न

The ionic radii of A+ and B are 0.98 × 10−10 m and 1.81 × 10−10 m. The coordination number of each ion in AB is ______.

विकल्प

  • 8

  • 2

  • 6

  • 4

MCQ
रिक्त स्थान भरें
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उत्तर

The ionic radii of A+ and B are 0.98 × 10−10 m and 1.81 × 10−10 m. The coordination number of each ion in AB is 6.

Explanation:

Given: Ionic radius of A+ = 0.98 × 10−10 m

Ionic radius of B = 1.81 × 10−10 m

Formula: Radius ratio = `(rA^+)/(rB^-)`

= `(0.98 xx 10^(−10))/(1.81 xx 10^(−10))`

= 0.54 ≈ 6

∴ The coordination number of each ion in AB is 6.

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अध्याय 6: Solid State - Evaluation [पृष्ठ १९८]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 6 Solid State
Evaluation | Q 9. | पृष्ठ १९८

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