हिंदी

The hypotenuse of a right-angled triangle is 20 meters. If the difference between the lengths of the other sides be 4 meters, find the other sides.

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प्रश्न

The hypotenuse of a right-angled triangle is 20 meters. If the difference between the lengths of the other sides be 4 meters, find the other sides. 

योग
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उत्तर

Let one side of the right-angled triangle be x m and the other side be (x + 4) m.

On applying Pythagoras theorem, we have: 

202 = (x + 4)2 + x2 

⇒ 400 = x2 + 8x + 16 + x2 

⇒ 2x2 + 8x – 384 = 0 

⇒ x2 + 4x – 192 = 0

⇒ x2 + (16 – 12)x – 192 = 0 

⇒ x2 + 16x – 12x – 192 = 0 

⇒ x2(x + 16) – 12(x + 16) = 0 

⇒ (x + 16) (x – 12) = 0 

⇒ x = –16 or x = 12 

The value of x cannot be negative.

Therefore, the base is 12 m and the other side is {(12 + 4) = 16 m}.

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अध्याय 4: Quadratic Equations - EXERCISE 4D [पृष्ठ २२९]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 4 Quadratic Equations
EXERCISE 4D | Q 69. | पृष्ठ २२९
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