Question

The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.

Answer 1

Let the two numbers be a and b.

Let the value of a be 161.

Given: HCF = 23 and LCM = 1449

We know, a × b = HCF × LCM

⇒ 161 × b = 23 × 1449

⇒ ∴ b = `(23 xx 1449)/161` 

= `33327/161`

= 207

Hence, the other number b is 207.