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प्रश्न
The function f(x) = x2 – 4x + 6 is increasing in the interval:
विकल्प
(0, 2)
(–∞, 2]
[1, 2]
[2, ∞)
MCQ
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उत्तर
[2, ∞)
Explanation:
f(x) = x2 – 4x + 6
f'(x) = 2x – 4
For critical points 2x – 4 = 0
⇒ x = 2
∴ Intervals (–∞, 2), (2, ∞)
Sign of f'(x) = 2x – 4
In (–∞, 2) f'(0) = − 4 < 0 ...(∴ Decreasing)
(2, ∞) f'(3) = 6 − 4 = 2 > 0 ...(∴ Increasing)
Hence, the functionf(x) is increasing in the interval [2, ∞).
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