Question

The force per unit length between two long parallel current-carrying conductors carrying currents I₁ and I₂, separated by a perpendicular distance d, is given by:

विकल्प

• \[\frac{F}{l}=\frac{\mu_0 I_1 I_2}{2\pi d^2}\]

• \[\frac{F}{l}=\frac{\mu_0 I_1 I_2}{4\pi d}\]

• \[\frac{F}{l}=\frac{2\pi d}{\mu_0 I_1 I_2}\]

• \[\frac{F}{l}=\frac{\mu_0 I_1 I_2}{2\pi d}\]

Answer 1

The force between two parallel current-carrying conductors is F = (μ₀I₁I₂/2πd) × l, so per unit length F/l = μ₀I₁I₂/(2πd). This force acts along the line joining the wires.