Advertisements
Advertisements
प्रश्न
The following table shows the number of saplings planted by 30 students. Fill in the boxes and find the average number of saplings planted by each student.
| No. of saplings (Scores) xi |
No. of students (frequency) fi |
fi x xi |
| 1 | 4 | 4 |
| 2 | 6 | `square` |
| 3 | 12 | `square` |
| 4 | 8 | `square` |
| N = `square` | ∑fixi = `square` |
Mean `bar "x"` = `square/"N"`
= `square/square`
= `square`
∴ The average number of trees planted `square`
Advertisements
उत्तर
| No. of saplings (Scores) xi |
No. of students (frequency) fi |
fi×xi |
| 1 | 4 | 4 |
| 2 | 6 | = 2 × 6 = 12 |
| 3 | 12 | = 3 × 12 = 36 |
| 4 | 8 | = 4 × 8 = 32 |
| N = 30 | ∑fixi = 84 |
Mean `bar "x"` = `bb((sum f_ix_x))/"N"`
= `bb(84/30)`
= 2.8
∴ The average number of trees planted is 2.8.
संबंधित प्रश्न
There are 40 students in a class, out of them 15 are boys. The mean of marks obtained by boys is 33 and that for girls is 35. Find out the mean of all students in the class.
Mean of 100 observations is 40. The 9th observation is 30. If this is replaced by 70 keeping all other observations same, find the new mean.
The mean of a set of numbers is `bar(X)`. If each number is multiplied by z, the mean is
Ages of 15 students in 8th standard is 13, 12, 13, 14, 12, 13, 13, 14, 12, 13, 13, 14, 13, 12, 14. Find the mean age of the students
The mean height of 11 students in a group is 150 cm. The heights of the students are 154 cm, 145 cm, Y cm, Y + 4 cm, 160 cm, 151 cm, 149 cm, 149 cm, 150 cm, 144 cm and 140 cm. Find the value of Y and the heights of two students?
Find the mean of the following data.
5.1, 4.8, 4.3, 4.5, 5.1, 4.7, 4.5, 5.2, 5.4, 5.8, 4.3, 5.6, 5.2, 5.5
_______________ is a representative value of the entire data
Mean of the data is always from the given data.
The marks in a subject for 12 students are as follows:
31, 37, 35, 38, 42, 23, 17, 18, 35, 25, 35, 29
For the given data, find the mean
Find the mean of first six multiples of 4.
