Question

The following table shows the funds collected by 105 students for flood-affected people. Find the median of the data.

Fund (Rupees)	No. of Students
10 - 20	10
20 - 30	37
30 - 40	15
40 - 50	20
50 - 60	7
60 - 70	8
70 - 80	8

Answer 1

Fund (Rupees)	No. of Students	Cumulative frequency (C.f.)
10 - 20	10	10
20 - 30	37	47
30 - 40	15	62
40 - 50	20	82
50 - 60	7	89
60 - 70	8	97
70 - 80	8	105
	(N) = 105

`N/2`

= `105/2`

= 52.5

The value just greater than 52.5 is 62. This corresponds to the class 30 - 40.

Median Class = 30 - 40

l = 30, f = 15, Cf = 47, h = 10

Median = `l + [((N/2 - Cf))/f] xx h`

= `30 + [((52.5 - 47))/15] xx 10`

= `30 + 55/15`

= 30 + 3.67

= 33.67