Advertisements
Advertisements
प्रश्न
The following data gives the average life(in hours) and range of 12 samples of 5lamps each. The data are
| Sample No | 1 | 2 | 3 | 4 | 5 | 6 |
| Sample Mean | 1080 | 1390 | 1460 | 1380 | 1230 | 1370 |
| Sample Range | 410 | 670 | 180 | 320 | 690 | 450 |
| Sample No | 7 | 8 | 9 | 10 | 11 | 12 |
| Sample Mean | 1310 | 1630 | 1580 | 1510 | 1270 | 1200 |
| Sample Range | 380 | 350 | 270 | 660 | 440 | 310 |
Construct control charts for mean and range. Comment on the control limits.
Advertisements
उत्तर
| Sample No | Sample Mean `bar"X"` |
Sample Range R |
| 1 | 1080 | 410 |
| 2 | 1390 | 670 |
| 3 | 1460 | 180 |
| 4 | 1380 | 320 |
| 5 | 1230 | 690 |
| 6 | 1370 | 450 |
| 7 | 1310 | 380 |
| 8 | 1630 | 350 |
| 9 | 1580 | 270 |
| 10 | 1510 | 660 |
| 11 | 1270 | 440 |
| 12 | 1200 | 310 |
| Total | `sum"X"` = 16410 | `sum"R"` = 5130 |
The control limits for `bar"X"` chart is
`\overset{==}{"X"} = (sum"X")/"Number of sample" = 16410/12` = 1367.5
`bar"R" = (sum"R")/"n" = 5130/12` = 427.5
UCL = `\overset{==}{"X"} + "A"_2 bar"R"`
= 1367.5 + 0.577(427.5)
= 1367.5 + 246.6675
= 1614.1675
= 1614.17
CL = `\overset{==}{"X"} ` = 1367.5
LCL = `\overset{==}{"X"} + "A"_2 bar"R"`
= 1367.5 – 0.577(427.5)
= 1367.5 – 246.6675
= 1120.8325
= 1120.83
The control limits for Range chart is
UCL = `"D"_4bar"R"`
= 2.115(427.5)
= 904.1625
= 904.16
CL = `bar"R"` = 427.5
LCL = `"D"_3bar"R"`
= 0(427.5)
= 0
APPEARS IN
संबंधित प्रश्न
Define Statistical Quality Control
What do you mean by product control?
Define R chart
Write the control limits for the R chart
The following data show the values of sample mean `(bar"X")` and its range (R) for the samples of size five each. Calculate the values for control limits for mean, range chart and determine whether the process is in control.
| Sample Number | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Mean | 11.2 | 11.8 | 10.8 | 11.6 | 11.0 | 9.6 | 10.4 | 9.6 | 10.6 | 10.0 |
| Range | 7 | 4 | 8 | 5 | 7 | 4 | 8 | 4 | 7 | 9 |
(conversion factors for n = 5, A2 = 0.58, D3 = 0 and D4 = 2.115)
In a production process, eight samples of size 4 are collected and their means and ranges are given below. Construct mean chart and range chart with control limits.
| Samples number | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| `bar"X"` | 12 | 13 | 11 | 12 | 14 | 13 | 16 | 15 |
| R | 2 | 5 | 4 | 2 | 3 | 2 | 4 | 3 |
Choose the correct alternative:
Variations due to natural disorder is known as
Choose the correct alternative:
The assignable causes can occur due to
Choose the correct alternative:
A typical control charts consists of
From the following data, calculate the control limits for the mean and range chart.
| Sample No. | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Sample Observations |
50 | 21 | 50 | 48 | 46 | 55 | 45 | 50 | 47 | 56 |
| 55 | 50 | 53 | 53 | 50 | 51 | 48 | 56 | 53 | 53 | |
| 52 | 53 | 48 | 50 | 44 | 56 | 53 | 54 | 549 | 55 | |
| 49 | 50 | 52 | 51 | 48 | 47 | 48 | 53 | 52 | 54 | |
| 54 | 46 | 47 | 53 | 47 | 51 | 51 | 47 | 54 | 52 |
