Question

The equation of the plane which is parallel to 2x − 3y + z = 0 and which passes through (1, −1, 2) is:

विकल्प

• 2x − 3y + z − 7 = 0

• 2x − 3y + z + 7 = 0

• 2x − 3y + z − 8 = 0

• 2x − 3y + z + 6 = 0

Answer 1

2x − 3y + z − 7 = 0

Explanation:

Given, 2x − 3y + z = 0 ......(i)

Equation of plane parallel to (i) is,

2x − 3y + z = d ...........(ii)

Which is passes through (1, −1, 2), then

2 × 1 − 3 × (− 1) + 2 = d

⇒ d = 7

Now from (ii), we get

2x − 3y + z = 7

or 2x − 3y + z − 7 = 0