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प्रश्न
The electron affinity of an element X is greater than that of element Y.
How is the oxidising power of X likely to compare with that of Y?
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उत्तर
Oxidising power of X > Y. Elements with high electron affinity accept electrons more easily and hence have greater oxidising power.
संबंधित प्रश्न
Arrange the following as per the instruction given in the brackets:
He, Ar, Ne (Increasing order of the number of electron shells)
Draw an electron dot diagram to show the formation of the following compound:
Methane
[H = 1, C = 6]
Give reason:
Electronegativity of chorine is higher than Sulphur?
Explain the following:
The reducing power of element increases down in the group while decreases in a period.
Arrange the following according to the instruction given in the bracket:
F, B, N, O (In the increasing order of electron affinity).
A, B, C are three elements in which B is an inert gas other than helium.With this information complete the following table.
| Element | Atomic number | No. of electrons in the valence shell | Group to which the element belongs |
| A | Z - 1 | ||
| B | Z | ||
| C | Z + 1 |
Also, explain the following : Electron affinity of B is Zero.
Among the Period 2 elements, the element which has high electron affinity is
On descending a group, ______ in ionisation potential as well as electron affinity ______ oxidising capacity.
Neon shows zero electron affinity due to ______.
The electron affinity of an element X is greater than that of element Y.
How is the electronegativity of X likely to compare with that of Y?
