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The discrete random variable X has the following probability function.P(X = x) = k,,kotherwise{kx x=2, 4, 6k(x-2) x=80 otherwisewhere k is a constant. Show that k = 118 - Business Mathematics and Statistics

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प्रश्न

The discrete random variable X has the following probability function.
P(X = x) = `{{:("k"x,  x = 2","  4","  6),("k"(x - 2),  x = 8),(0,  "otherwise"):}`
where k is a constant. Show that k = `1/18`

योग
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उत्तर

From the data

P(x = 2) = kx

= 2k

P(x = 4) = kx

= 4k

P(x = 6) = kx

= 6k

P(x = 8) = k(x – 2)

= k(8 – 2) = 6k

Since P(X = x) is a probability mass function

`sum_(x = 2)^8` P(X = x) = 1

`sum_("i" = 2)^oo` P(xi) = 1

i.e P(x = 2) + P(x = 4) + P(x = 6) + P(x = 8) = 1

2k + 4k + 6k + 6k = 1

18k = 1

∴ k = `1/18`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Random Variable and Mathematical expectation - Exercise 6.1 [पृष्ठ १३२]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 6 Random Variable and Mathematical expectation
Exercise 6.1 | Q 3 | पृष्ठ १३२

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