Advertisements
Advertisements
प्रश्न
The difference of the squares of two consecutive numbers is their sum.
विकल्प
True
False
Advertisements
उत्तर
This statement is True.
Explanation:
Let two consecutive numbers be x and (x + 1).
Then squares of these numbers are x2 and (x + 1)2.
Difference of squares of these consecutive numbers = (x + 1)2 – x2
= x2 + 1 + 2x – x2 ...[∵ (a + b)2 = a2 + b2 + 2ab)
= 2x + 1
= x + x + 1
= (x) + (x + 1)
= Sum of the two consecutive numbers x and x + 1
Thus, difference of squares of two consecutive numbers = sum of the same consecutive numbers.
APPEARS IN
संबंधित प्रश्न
Use a suitable identity to get the following products.
(a2 + b2) (− a2 + b2)
Simplify (a2 − b2)2
Using identities, evaluate 8.92
Use a formula to multiply of (2t – 5)(2t + 5)
If a + b = 10 and ab = 18, find the value of a2 + b2
Using identity, find the value of (100.1)2
Show that (x + 2y)2 – (x – 2y)2 = 8xy
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2ax + 1
Factorise the following.
p2 + 14p + 13
What should be added to 4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)?
