Advertisements
Advertisements
प्रश्न
The difference between two positive numbers is 5 and the sum of their squares is 73. Find the product of these numbers.
Advertisements
उत्तर
Let the two positive numbers be a and b.
Given difference between them is 5 and sum of squares is 73.
So a - b = 5, a2 + b2 = 73
Squaring on both sides gives
(a - b)2 = 52
a2 + b2 - 2ab = 25
but a2 + b2 = 73
so 2ab = 73 - 25 = 48
ab = 24
So, the product of numbers is 24.
APPEARS IN
संबंधित प्रश्न
Expand the following, using suitable identity:
(–2x + 5y – 3z)2
Factorise:
4x2 + 9y2 + 16z2 + 12xy – 24yz – 16xz
If `x + 1/x = sqrt5`, find the value of `x^2 + 1/x^2` and `x^4 + 1/x^4`
Evaluate of the following:
1043 + 963
Simplify of the following:
(x+3)3 + (x−3)3
Find the following product:
If a + b = 8 and ab = 6, find the value of a3 + b3
Use the direct method to evaluate :
(2+a) (2−a)
Use the direct method to evaluate :
(0.5−2a) (0.5+2a)
If a - b = 10 and ab = 11; find a + b.
