Advertisements
Advertisements
प्रश्न
The difference between two positive numbers is 4 and the difference between their cubes is 316.
Find : Their product
Advertisements
उत्तर
Given difference between two positive numbers is 4 and difference between their cubes is 316.
Let the positive numbers be a and b
a - b = 4
a3 - b3 = 316
Cubing both sides,
(a - b)3 = 64
a3 - b3 - 3ab(a - b) = 64
Given a3 - b3 = 316
So 316 - 64 = 3ab(4)
252 = 12ab
So ab = 21; product of numbers is 21
APPEARS IN
संबंधित प्रश्न
Expand : ( x + 8 ) ( x + 10 )
Expand : ( X - 8 ) ( X + 10 )
Expand : ( 5x - 3y - 2 )2
Expand : `( x - 1/x + 5)^2`
If a2 + b2 + c2 = 35 and ab + bc + ca = 23; find a + b + c.
If x + 2y + 3z = 0 and x3 + 4y3 + 9z3 = 18xyz ; evaluate :
`[( x + 2y )^2]/(xy) + [(2y + 3z)^2]/(yz) + [(3z + x)^2]/(zx)`
If a + `1/a` = m and a ≠ 0 ; find in terms of 'm'; the value of :
`a - 1/a`
In the expansion of (2x2 - 8) (x - 4)2; find the value of constant term.
If a2 + b2 = 34 and ab = 12; find : 7(a - b)2 - 2(a + b)2
Find the value of 'a': 4x2 + ax + 9 = (2x - 3)2
