Advertisements
Advertisements
प्रश्न
If a + `1/a` = m and a ≠ 0 ; find in terms of 'm'; the value of :
`a - 1/a`
Advertisements
उत्तर
Given that a + `1/a` = m
Now consider the expansion of `( a + 1/a )^2` :
`( a + 1/a )^2 = a^2 + 1/a^2 + 2`
⇒ m2 = a2 + `1/a^2` + 2
⇒ a2 + `1/a^2` = m2 - 2
Now consider the expansion of `( a - 1/a )^2` :
`( a - 1/a )^2 = a^2 + 1/a^2 - 2`
⇒ `( a - 1/a )^2 = m^2 - 2 - 2`
⇒ `( a - 1/a )^2 = m^2 - 4`
⇒ `( a - 1/a ) = +-sqrt(m^2 - 4)`
APPEARS IN
संबंधित प्रश्न
Expand : ( x + 8 )( x - 10 )
Expand : ( X - 8 ) ( X + 10 )
Expand: `( 2x - 1/x )( 3x + 2/x )`
Expand : `( 3a + 2/b )( 2a - 3/b )`
Expand : ( x + y - z )2
Expand : ( 5a - 3b + c )2
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If 3x - `4/x` = 4; and x ≠ 0 find : 27x3 - `64/x^3`
