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The current in a coil changes from 50A to 10A in 0.1 second. The self inductance of the coil is 20H. The induced e.m.f. in the coil is ______.

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प्रश्न

The current in a coil changes from 50A to 10A in 0.1 second. The self inductance of the coil is 20H. The induced e.m.f. in the coil is ______.

विकल्प

  • 800V

  • 6000V

  • 7000V

  • 8000V

MCQ
रिक्त स्थान भरें
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उत्तर

The current in a coil changes from 50A to 10A in 0.1 second. The self-inductance of the coil is 20H. The induced e.m.f. in the coil is 8000V.

Explanation:

The induced e.m.f. in the coil is given by the formula:

e.m.f. = `-L(DeltaI)/(Deltat)`

Where,

L= 20H (self-inductance)

ΔI = final​ − Iinitial ​= 10A − 50A = −40A,

Δt = 0.1 s.

Substituting the values:

e.m.f. = `-20 xx (-40)/0.1 = 20 xx 400 8000 V`

The magnitude of the induced emf is 8000 V.

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