हिंदी

The compound in its pure form turns into an ice like solid on cooling. - Chemistry

Advertisements
Advertisements

प्रश्न

The compound in its pure form turns into an ice like solid on cooling.

विकल्प

  • Ethene

  • Ethanoic acid

  • Ethanol

  • Methanal

MCQ
Advertisements

उत्तर

Ethanoic acid

Explanation:

Melting point of ethanoic acid is 289.5 K, or 16°C. It so freezes below this temperature and is also known as glacial acetic acid.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2023-2024 (March) Official

संबंधित प्रश्न

Name an organic compound which is Made from water gas ?


Give the various applications of organic chemistry?


Explain the fact that why organic com pounds are Iarge in number.


What is an alkyl group?


What are the main sources of alkanes and why they are known as saturated hydrocarbons?


What are addition reactions? Why ethene undergo addition reactions? Give
two examples.


Give the reactions of ethyne with Hydrogen



Write balanced euation for the following :

Write the general formula for a saturated hydrocarbon and give one example of a saturated hydrocarbon with its structural formula.


Distinguish between the saturated hydrocarbon ethane and the unsaturated hydrocarbon ethene by drawing their structural formulae.


The structures of six organic compounds are shown:

A

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C = C - C - H}\\
|\phantom{.............}|\\
\ce{H}\phantom{............}\ce{H}
\end{array}\]

B

\[\begin{array}{cc}
\phantom{.......}\ce{H}\phantom{.....}\ce{O}\\
\phantom{.......}|\phantom{.....}//\\
\ce{H - C - C}\\
\phantom{......}|\phantom{.....}\backslash\\
\phantom{...........}\ce{H}\phantom{.....}\ce{O - H}
\end{array}\]

C

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

D

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{O}\\
\phantom{.......}\backslash\\
\phantom{.........}\ce{H}
\end{array}\]

E

\[\begin{array}{cc}
\ce{H}\\
|\\
\ce{H - C - H}\\
\ce{H}\phantom{....}\phantom{....}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

F

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{C = C}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}
\end{array}\]

  1. Identify two of the compounds that are members of the same homologous series but are not isomers.
  2. Which two compounds are isomers of each other?
  3. F can be prepared from D. Give a chemical equation for the reaction.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×