हिंदी

The compound in its pure form turns into an ice like solid on cooling.

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प्रश्न

The compound in its pure form turns into an ice like solid on cooling.

विकल्प

  • Ethene

  • Ethanoic acid

  • Ethanol

  • Methanal

MCQ
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उत्तर

Ethanoic acid

Explanation:

Melting point of ethanoic acid is 289.5 K, or 16°C. It so freezes below this temperature and is also known as glacial acetic acid.

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संबंधित प्रश्न

Give the names of any three alkyl groups. How are they formed?


Name the following:

Catalyst used in the Esterification reaction.


Write the equation for the laboratory preparation of Ethyne (acetylene) from calcium carbide.


What would you see when ethyne is bubbled through a solution of bromine in carbon tetrachloride?


Name the addition product formed between ethane and water.


The organic compound mixed with ethanol to make it spurious is ______.


Give a chemical term for a reaction in which hydrogen of a alkane is replaced by a halogen


Using the structural formula, identify the functional group by circling it:

Dimethyl ether


Name the following:

Process by which ethane is obtained from ethene.


The structures of six organic compounds are shown:

A

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C = C - C - H}\\
|\phantom{.............}|\\
\ce{H}\phantom{............}\ce{H}
\end{array}\]

B

\[\begin{array}{cc}
\phantom{.......}\ce{H}\phantom{.....}\ce{O}\\
\phantom{.......}|\phantom{.....}//\\
\ce{H - C - C}\\
\phantom{......}|\phantom{.....}\backslash\\
\phantom{...........}\ce{H}\phantom{.....}\ce{O - H}
\end{array}\]

C

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

D

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{O}\\
\phantom{.......}\backslash\\
\phantom{.........}\ce{H}
\end{array}\]

E

\[\begin{array}{cc}
\ce{H}\\
|\\
\ce{H - C - H}\\
\ce{H}\phantom{....}\phantom{....}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

F

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{C = C}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}
\end{array}\]

  1. Identify two of the compounds that are members of the same homologous series but are not isomers.
  2. Which two compounds are isomers of each other?
  3. F can be prepared from D. Give a chemical equation for the reaction.

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