Question

The code given below accepts a number as an argument and returns the reverse number. Observe the following code carefully and rewrite it after removing all syntax and logical errors. Underline all the corrections made.

define revNumber (num) :
      rev = 0
      rem = 0
      While num > 0:
            rem ==num %10
            rev = rev*10 + rem
            num = num//10
            return rev
print (revNumber (1234))

Answer 1

def revNumber (num) :
          rev = 0
          rem = 0
          while num > 0:
               rem =num %10
               rev = rev*10 + rem
               num = num//10
       return rev
print (revNumber (1234))