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The Area of Sector of Circle of Radius 2cm is ЁЭЬЛCm2. Find the Angle Contained by the Sector.

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The area of sector of circle of radius 2cm is ЁЭЬЛcm2. Find the angle contained by the sector.

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Area of sector = ЁЭЬЛ ЁЭСРЁЭСЪ2

Radius of circle = 2ЁЭСРЁЭСЪ

Let ЁЭЬГ = angle subtended by arc at centre

Area of sector =`theta/360^@× pir^2`

=`theta/360^@× pi× 2 × 2`

=`(pitheta)/90^@`

`(pitheta)/90^@`= ЁЭЬЛ ⇒ ЁЭЬГ = 90°

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