हिंदी

The Area Bounded by The Y-axis, Y = Cos X And Y = Sin X When 0 <= X <= `Pi/2` - Mathematics

Advertisements
Advertisements

प्रश्न

The area bounded by the y-axis, y = cos x and y = sin x when  0 <= x <= `pi/2`

(A) 2 ( 2 −1)

(B) `sqrt2 -1`

(C) `sqrt2 + 1`

D. `sqrt2`

Advertisements

उत्तर

The given equations are

y = cos x … (1)

And, y = sin x … (2)

Required area = Area (ABLA) + area (OBLO)

Thus, the correct answer is B.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Application of Integrals - Exercise 8.3 [पृष्ठ ३७६]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 8 Application of Integrals
Exercise 8.3 | Q 19 | पृष्ठ ३७६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Using integration, find the area of the region bounded by the triangle whose vertices are (−1, 2), (1, 5) and (3, 4).


Find the area of the region lying between the parabolas y2 = 4ax and x2 = 4ay.


Find the area of the region bounded by the curves y = x+ 2, xx = 0 and x = 3


Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is

A. 2 (π – 2)

B. π – 2

C. 2π – 1

D. 2 (π + 2)


Using the method of integration find the area bounded by the curve |x| + |y| = 1 .

[Hint: The required region is bounded by lines x + y = 1, x– y = 1, – x + y = 1 and
– x – y = 1].


Find the area bounded by curves {(x, y) : y ≥ x2 and y = |x|}.


Choose the correct answer The area of the circle x2 + y2 = 16 exterior to the parabola y2 = 6x is

A. `4/3 (4pi - sqrt3)`

B. `4/3 (4pi + sqrt3)`

C. `4/3 (8pi - sqrt3)`

D.`4/3 (4pi + sqrt3)`


Using integration, find the area of region bounded by the triangle whose vertices are (–2, 1), (0, 4) and (2, 3).


Find the area included between the parabolas y2 = 4ax and x2 = 4by.


The area enclosed between the curves y = loge (x + e), x = log\[\left( \frac{1}{y} \right)\] and the x-axis is _______ .


Area enclosed between the curve y2 (2a − x) = x3 and the line x = 2a above x-axis is ___________ .


Solve the following :

Find the area of the region lying between the parabolas y2 = 4x and x2 = 4y.


The area of the region included between the parabolas y2 = 16x and x2 = 16y, is given by ______ sq.units


The area of triangle ΔABC whose vertices are A(1, 1), B(2, 1) and C(3, 3) is ______ sq.units


Find the area enclosed between y = cos x and X-axis between the lines x = `pi/2` and x ≤ `(3pi)/2`


Find the area of the ellipse `x^2/1 + y^2/4` = 1, in first quadrant


Find the area of the region lying between the parabolas 4y2 = 9x and 3x2 = 16y


Find the area of the region included between the parabola y = `(3x^2)/4` and the line 3x – 2y + 12 = 0.


Find the area of a minor segment of the circle x2 + y2 = a2 cut off by the line x = `"a"/2`


Determine the area under the curve y = `sqrt("a"^2 - x^2)` included between the lines x = 0 and x = a.


Area lying between the curves `y^2 = 4x` and `y = 2x`


Let the area enclosed by the x-axis, and the tangent and normal drawn to the curve 4x3 – 3xy2 + 6x2 – 5xy – 8y2 + 9x + 14 = 0 at the point (–2, 3) be A. Then 8A is equal to ______.


Using Integration, find the area of triangle whose vertices are (– 1, 1), (0, 5) and (3, 2).


Find the area cut off from the parabola 4y = 3x2 by the line 2y = 3x + 12.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×