हिंदी

The area bounded by the curve y = x | x|, x-axis and the ordinates x = –1 and x = 1 is given by ______. [Hint: y = x2 if x > 0 and y = –x2 if x < 0] - Mathematics

Advertisements
Advertisements

प्रश्न

The area bounded by the curve y = x | x|, x-axis and the ordinates x = –1 and x = 1 is given by ______.

[Hint: y = x2 if x > 0 and y = –x2 if x < 0]

विकल्प

  • 0

  • `1/3`

  • `2/3`

  • `4/3`

MCQ
रिक्त स्थान भरें
Advertisements

उत्तर

The area bounded by the curve y = x | x|, x-axis and the ordinates x = –1 and x = 1 is given by `underline(2/3)`. 

Explanation:

When x > 0, |x| = x

∴ Equation of the curve  y = x2

When x < 0, |x| = -x

Equation of the curve y = -x2

Curve y = x |x|, x ≥ -1, x ≤ 0

The area bounded by x-axis = Area of ​​region APO + Area of ​​region OBQ

`= |int_(-1)^0 - x^2 dx| + int_0^1 x^2 dx`

`= |[-x^3/3]|_-1^0 + [x^3/3]_0^1`

`= |-0 - 1/3| + [1/3 - 0]`

`= 1/3 + 1/3`

`= 2/3` square unit

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Application of Integrals - Exercise 8.3 [पृष्ठ ३७६]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 8 Application of Integrals
Exercise 8.3 | Q 17 | पृष्ठ ३७६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the area of the region lying in the first quandrant bounded by the curve y2= 4x, X axis and the lines x = 1, x = 4


Find the equation of a curve passing through the point (0, 2), given that the sum of the coordinates of any point on the curve exceeds the slope of the tangent to the curve at that point by 5


Find the area under the curve y = \[\sqrt{6x + 4}\] above x-axis from x = 0 to x = 2. Draw a sketch of curve also.


Sketch the graph y = |x + 1|. Evaluate\[\int\limits_{- 4}^2 \left| x + 1 \right| dx\]. What does the value of this integral represent on the graph?


Find the area bounded by the curve y = cos x, x-axis and the ordinates x = 0 and x = 2π.


Find the area of the region bounded by the curve \[x = a t^2 , y = 2\text{ at }\]between the ordinates corresponding t = 1 and t = 2.


Using integration, find the area of the region bounded by the triangle ABC whose vertices A, B, C are (−1, 1), (0, 5) and (3, 2) respectively.


Find the area common to the circle x2 + y2 = 16 a2 and the parabola y2 = 6 ax.
                                   OR
Find the area of the region {(x, y) : y2 ≤ 6ax} and {(x, y) : x2 + y2 ≤ 16a2}.


Using integration find the area of the region bounded by the curves \[y = \sqrt{4 - x^2}, x^2 + y^2 - 4x = 0\] and the x-axis.


If the area enclosed by the parabolas y2 = 16ax and x2 = 16ay, a > 0 is \[\frac{1024}{3}\] square units, find the value of a.


Find the area bounded by the parabola y2 = 4x and the line y = 2x − 4 By using horizontal strips.


The area included between the parabolas y2 = 4x and x2 = 4y is (in square units)


The area bounded by y = 2 − x2 and x + y = 0 is _________ .


If An be the area bounded by the curve y = (tan x)n and the lines x = 0, y = 0 and x = π/4, then for x > 2


The area bounded by the curves y = sin x between the ordinates x = 0, x = π and the x-axis is _____________ .


The area bounded by the parabola y2 = 4ax, latusrectum and x-axis is ___________ .


The closed area made by the parabola y = 2x2 and y = x2 + 4 is __________ .


The area of the circle x2 + y2 = 16 enterior to the parabola y2 = 6x is


Find the area of the region above the x-axis, included between the parabola y2 = ax and the circle x2 + y2 = 2ax.


Find the area of the region bounded by the curve y = x3 and y = x + 6 and x = 0


Find the area of the region bounded by y = `sqrt(x)` and y = x.


Find the area bounded by the curve y = `sqrt(x)`, x = 2y + 3 in the first quadrant and x-axis.


Find the area of region bounded by the triangle whose vertices are (–1, 1), (0, 5) and (3, 2), using integration.


Area of the region bounded by the curve y = cosx between x = 0 and x = π is ______.


The area of the region bounded by parabola y2 = x and the straight line 2y = x is ______.


The area of the region bounded by the circle x2 + y2 = 1 is ______.


Using integration, find the area of the region `{(x, y): 0 ≤ y ≤ sqrt(3)x, x^2 + y^2 ≤ 4}`


Let f(x) be a continuous function such that the area bounded by the curve y = f(x), x-axis and the lines x = 0 and x = a is `a^2/2 + a/2 sin a + pi/2 cos a`, then `f(pi/2)` =


Find the area of the region bounded by `x^2 = 4y, y = 2, y = 4`, and the `y`-axis in the first quadrant.


Find the area of the region bounded by curve 4x2 = y and the line y = 8x + 12, using integration.


Area (in sq.units) of the region outside `|x|/2 + |y|/3` = 1 and inside the ellipse `x^2/4 + y^2/9` = 1 is ______.


The area of the region bounded by the parabola (y – 2)2 = (x – 1), the tangent to it at the point whose ordinate is 3 and the x-axis is ______.


The area (in square units) of the region bounded by the curves y + 2x2 = 0 and y + 3x2 = 1, is equal to ______.


Sketch the region bounded by the lines 2x + y = 8, y = 2, y = 4 and the Y-axis. Hence, obtain its area using integration.


Find the area of the minor segment of the circle x2 + y2 = 4 cut off by the line x = 1, using integration.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×