Question

The angle of elevation of the top of a 15 m high tower at a point `15sqrt(3)` m away from the base of the tower is ______.

विकल्प

• 30°

• 45°

• 60°

• 90°

Answer 1

The angle of elevation of the top of a 15 m high tower at a point `15sqrt(3)` m away from the base of the tower is 30°.

Explanation:

Let the angle be x

So, tan x = `15/(15sqrt(3))`

= `1/sqrt(3)`

`\implies` tan x = tan 30°

So, Angle of elevation = 30°