हिंदी

The Amount of Extension in an Elastic Spring Varies Directly with the Weight Hung on It. If a Weight of 250 Gm Produces an Extension of 3.5 Cm, Find the Extension Produced by the Weight of 700 Gm.

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प्रश्न

The amount of extension in an elastic spring varies directly with the weight hung on it. If a weight of 250 gm produces an extension of 3.5 cm, find the extension produced by the weight of 700 gm.

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उत्तर

Let x cm be the extension produced by the weight of 700 gm.
 

Weight (in gm) 250 700
Length (in cm) 3.5 x

\[\text{ Since the amount of extension in an elastic spring varies and the weight hung on it is in direct variation, we have } : \]
\[\frac{250}{700} = \frac{3 . 5}{x}\]
\[ \Rightarrow x \times 250 = 3 . 5 \times 700\]
\[ \Rightarrow x = \frac{3 . 5 \times 700}{250}\]
\[ = \frac{2450}{250}\]
\[ = 9 . 8\]
\[\text{ Thus, the required extension will be 9 . 8 cm }  .\]

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अध्याय 10: Direct and Inverse Variations - Exercise 10.1 [पृष्ठ ८]

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आरडी शर्मा Mathematics [English] Class 8
अध्याय 10 Direct and Inverse Variations
Exercise 10.1 | Q 21 | पृष्ठ ८

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