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प्रश्न
The acute angle between the lines `(x - 1)/1 = (y - 2)/-1 = (z - 3)/2 and (x - 1)/2 = (y - 2)/1 = (z - 3)/2` is ______.
विकल्प
60°
30°
45°
90°
MCQ
रिक्त स्थान भरें
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उत्तर
The acute angle between the lines `(x - 1)/1 = (y - 2)/-1 = (z - 3)/2 and (x - 1)/2 = (y - 2)/1 = (z - 3)/2` is 60°.
Explanation:
Given equations of lines are `(x - 1)/1 = (y - 2)/(-1) = (z - 3)/2` and `(x - 1)/2 = (y - 1)/1 = (z - 3)/1`
Direction ratios of above lines are
a1 = 1, b1 = −1, c1 = 2 and a2 = 2, b2 = 1, c2 = 1
Angle between two lines is
cos θ = `|(a_1a_2 + b_1b_2 + c_1c_2)/(sqrt(a_1^2 + b_1^2 + c_1^2) sqrt(a_2^2 + b_2^2 + c_2^2))|`
∴ cos θ = `|((1)(2) + (-1)(1) + (2)(1))/(sqrt(1^2 + (-1)2 + 2^2 sqrt(2^2 + 1^2 + 1^2))|`
∴ cos θ = `|(2 - 1 + 2)/(sqrt(6)sqrt(6))|`
∴ cos θ = `|3/6|`
∴ θ = `cos^-1(1/2)`
∴ θ = 60°
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