हिंदी

The 4th term of a G.P. is 16 and the 7th term is 128, then its common ratio is equal to ______.

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प्रश्न

The 4th term of a G.P. is 16 and the 7th term is 128, then its common ratio is equal to ______.

विकल्प

  • 2

  • −2

  • 1

  • −1

MCQ
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उत्तर

The 4th term of a G.P. is 16 and the 7th term is 128, then its common ratio is equal to 2.

Explanation:

Let first term of G.P. be a and common ratio be r.

By formula,

⇒ an = arn − 1

Given,

4th term of a G.P. is 16.

⇒ a4 = 16

⇒ ar4 − 1 = 16

⇒ ar3 = 16   .........(1)

Given,

7th term of a G.P. is 128.

⇒ a7 = 128

⇒ ar7 − 1 = 128

⇒ ar6 = 128 .........(2)

Dividing equation (2) by (1), we get:

⇒ `(ar^6)/(ar^3) = 128/16`

⇒ r3 = 8

⇒ r3 = 23

⇒ r = 2

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अध्याय 11: Geometric Progression - Exercise 11 (A) [पृष्ठ १५०]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 11 Geometric Progression
Exercise 11 (A) | Q 1. (b) | पृष्ठ १५०
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