हिंदी

The 24th term of an A.P. exceeds its 19th term by 10, its common difference is ______.

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प्रश्न

The 24th term of an A.P. exceeds its 19th term by 10, its common difference is ______.

विकल्प

  • 5

  • 2

  • 10

  • 1

MCQ
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उत्तर

The 24th term of an A.P. exceeds its 19th term by 10, its common difference is 2.

Explanation:

Let a be the first term and d be the common difference between provided A.P.

Given T24 = T19 + 10

⇒ a + 23d = a + 18d + 10

⇒ 23d – 18d = 0

⇒ 5d = 10

⇒ d = 2

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अध्याय 10: Arithmetic Progression - Exercise 10 (A) [पृष्ठ १३३]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 10 Arithmetic Progression
Exercise 10 (A) | Q 1. (d) | पृष्ठ १३३
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