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Suppose a girl throws a die. If she gets a 5 or 6, she tosses a coin three times and notes the number of heads. If she gets 1, 2, 3 or 4, she tosses a coin once and notes whether a head or tail is

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प्रश्न

Suppose a girl throws a die. If she gets a 5 or 6, she tosses a coin three times and notes the number of heads. If she gets 1, 2, 3 or 4, she tosses a coin once and notes whether a head or tail is obtained. If she obtained exactly one head, what is the probability that she threw 1, 2, 3 or 4 with the die?

योग
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उत्तर

Use value E1 = 5 or 6 to get

E2 = getting 1, 2, 3, or 4

n(E1) = 2, n(E2) = 4 n(s) = 6

P(E1) = `2/6 = 1/3`

P(E2) = `4/6 = 2/3`

Let E = one head is obtained

P(heads are obtained when the coin is tossed 3 times) = P(E|E1)

= P(HTT, THT, TTH)

= `3/8`

P(heads appear when the coin is tossed 1 time) = P(E|E2)

= `1/2`

Required process = `(1/2 xx 2/3)/((1/2 xx 2/3) + (3/8 xx 1/3))`

= `8/8 + 3`

= `8/11`

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अध्याय 13: Probability - Exercise 13.3 [पृष्ठ ५५७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 13 Probability
Exercise 13.3 | Q 10 | पृष्ठ ५५७

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