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Sunita is Twice as Old as Ashima. If Six Years is Subtracted from Ashima'S Age and Four Years Added to Sunita'S Age, Then Sunita Will Be Four Times Ashima'S Age. How Old Were They Two Years Ago? - Mathematics

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प्रश्न

Sunita is twice as old as Ashima. If six years is subtracted from Ashima's age and four years added to Sunita's age, then Sunita will be four times Ashima's age. How old were they two years ago?

संख्यात्मक
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उत्तर

Let the age of Ashima be x years . 
Therefore, the age of Sunita will be 2x years . 
According to the question, 
4(x - 6) = 2x + 4
or 4x - 24 = 2x + 4
or 4x - 2x = 4 + 24
or 2x = 28
or x = 14
∴Age of Ashima = 14 years . 
 Age of Sunita = 2 x 14 = 28 years .

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अध्याय 9: Linear Equation in One Variable - Exercise 9.4 [पृष्ठ ३०]

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आरडी शर्मा Mathematics [English] Class 8
अध्याय 9 Linear Equation in One Variable
Exercise 9.4 | Q 11 | पृष्ठ ३०
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