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Sum of two numbers is 5. If the sum of the cubes of these numbers is least, then find the sum of the squares of these numbers. - Mathematics

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प्रश्न

Sum of two numbers is 5. If the sum of the cubes of these numbers is least, then find the sum of the squares of these numbers.

योग
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उत्तर

Let two numbers be x and y then

x + y = 5  ...(i)

Let S = x3 + y3  ...(ii)

= x3 + (5 – x)3  ...[From (i)]

`(dS)/dx` = 3x2 + 3(5 – x)2 (– 1)

`(dS)/dx` = 3x2 – 3(25 + x2 – 10x)

= 3x2 – 75 – 3x2 + 30x

= 30x – 75

For maximum or minimum

`(dS)/dx` = 0

`\implies` 30x – 75 = 0

`\implies` x = `75/35 = 5/2`

When x = `5/2`, y = `5 - 5/2 = 5/2`  ...[From (i)]

`(d^2S)/(dx^2)` = 30 which is +ve.

So the sum is least when x = `5/2` and y = `5/2`

S = x2 + y2

= `25/4 + 25/4`

= `50/4`

= `25/2`

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