Sum of binomial coefficient in a particular expansion is 256, then number of terms in the expansion is:

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Binomial Theorem

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अध्याय 2: Algebra - Exercise 2.7 [पृष्ठ ४७]

अध्याय 2 Algebra
Exercise 2.7 | Q 23 | पृष्ठ ४७

Find the middle terms in the expansion of

`(3x + x^2/2)^8`

Find the middle terms in the expansion of

`(2x^2 - 3/x^3)^10`

Show that the middle term in the expansion of is (1 + x)²ⁿ is `(1*3*5...(2n - 1)2^nx^n)/(n!)`

The constant term in the expansion of `(x + 2/x)^6` is

Sum of the binomial coefficients is

Expand `(2x^2 -3sqrt(1 - x^2))^4 + (2x^2 + 3sqrt(1 - x^2))^4`

Compute 9⁷

In the binomial expansion of (1 + x)ⁿ, the coefficients of the 5^th, 6^th and 7^th terms are in AP. Find all values of n

Choose the correct alternative:
The value of 2 + 4 + 6 + … + 2n is

Choose the correct alternative:
The remainder when 38¹⁵ is divided by 13 is