Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
The value of 2 + 4 + 6 + … + 2n is
विकल्प
`("n"("n" - 1))/2`
`("n"("n" + 1))/2`
`(2"n"(2"n" + 1))/2`
n(n + 1)
Advertisements
उत्तर
n(n + 1)
APPEARS IN
संबंधित प्रश्न
Evaluate the following using binomial theorem:
(999)5
Expand the following by using binomial theorem.
(2a – 3b)4
Expand the following by using binomial theorem.
`(x + 1/y)^7`
Find the middle terms in the expansion of
`(x + 1/x)^11`
Find the term independent of x in the expansion of
`(x^2 - 2/(3x))^9`
Find the term independent of x in the expansion of
`(x - 2/x^2)^15`
Find the term independent of x in the expansion of
`(2x^2 + 1/x)^12`
The middle term in the expansion of `(x + 1/x)^10` is
The last term in the expansion of (3 + √2 )8 is:
Expand `(2x^2 - 3/x)^3`
Find the coefficient of x15 in `(x^2 + 1/x^3)^10`
Find the coefficient of x2 and the coefficient of x6 in `(x^2 -1/x^3)^6`
Find the coefficient of x4 in the expansion `(1 + x^3)^50 (x^2 + 1/x)^5`
Find the constant term of `(2x^3 - 1/(3x^2))^5`
If n is an odd positive integer, prove that the coefficients of the middle terms in the expansion of (x + y)n are equal
If a and b are distinct integers, prove that a − b is a factor of an − bn, whenever n is a positive integer. [Hint: write an = (a − b + b)n and expaand]
In the binomial expansion of (1 + x)n, the coefficients of the 5th, 6th and 7th terms are in AP. Find all values of n
Choose the correct alternative:
The remainder when 3815 is divided by 13 is
