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प्रश्न
Subtract the sum of 5y2 + y – 3 and y2 – 3y + 7 from 6y2 + y – 2.
योग
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उत्तर
5y2 + y – 3
y2 – 3y + 7
6y2 – 2y + 4
6y2 + y – 2
6y2 – 2y + 4
– + –
3y – 6
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Combining like Terms
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संबंधित प्रश्न
Evaluate :
b2y − 9b2y + 2b2y − 5b2y
Add : 5a + 3b, a − 2b, 3a + 5b
Add : 13ab − 9cd − xy, 5xy, 15cd − 7ab, 6xy − 3cd
Subtract : 4xy2 from 3xy2
Subtract : 3a − 5b + c + 2d from 7a − 3b + c − 2d
Subtract : 6a + 3 from a3 − 3a2 + 4a + 1
Subtract : a2 + ab + b2 from 4a2 − 3ab + 2b2
Take m2 + m + 4 from −m2 + 3m + 6 and the result from m2 + m + 1.
The perimeter of a triangle is 8y2 – 9y + 4 and its two sides are 3y2 – 5y and 4y2 + 12. Find its third side.
The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2. Find its perimeter.
