Question

Subtract:

3t⁴ – 4t³ + 2t² – 6t + 6 from – 4t⁴ + 8t³ – 4t² – 2t + 11

Answer 1

We have,

3t⁴ – 4t³ + 2t² – 6t + 6 and – 4t⁴ + 8t³ – 4t² – 2t + 11

The required difference is given by (– 4t⁴ + 8t³ – 4t² – 2t + 11) – (3t⁴ – 4t³ + 2t² – 6t + 6)

= – 4t⁴ + 8t³ – 4t² – 2t + 11 – 3t⁴ + 4t³ – 2t² + 6t – 6

= (– 4t⁴ – 3t⁴) + (8t³ + 4t³) + (– 4t² – 2t²) + (–2t + 6t) + (11 – 6)  ...[Grouping like terms]

= –7t⁴ + 12t³ – 6t² + 4t + 5