Advertisements
Advertisements
प्रश्न
State and explain Pauli's exclusion principle.
Advertisements
उत्तर
Pauli’s exclusion principle states that “No two electrons in an atom can have the same set of values of all four quantum numbers”.
Illustration: H(Z = 1) 1s1.
One electron is present in hydrogen atom, the four quantum numbers are n = 1, l = 0, m = 0 and s = `+1/2`. For helium Z = 2. He: 1s2. In this one electron has the quantum number same as that of hydrogen, n = 1, l = 0, m = 0 and s = `+1/2` For other electron, fourth quantum number is different, i.e. n = 1, l = 0, m = 0 and s = `-1/2`.
APPEARS IN
संबंधित प्रश्न
Electronic configuration of species M2+ is 1s2 2s2 2p6 3s2 3p6 3d6 and its atomic weight is 56. The number of neutrons in the nucleus of species M is
If n = 6, the correct sequence for filling of electrons will be,
The energy of an electron in the 3rd orbit of hydrogen atom is –E. The energy of an electron in the first orbit will be
Consider the following electronic arrangements for the d5 configuration.
| ⥮ | ⥮ | 1 | ||
| (a) | ||||
| 1 | 1 | 1 | ⥮ | |
| (b) | ||||
| 1 | 1 | 1 | 1 | 1 |
| (c) | ||||
- which of these represents the ground state.
- which configuration has the maximum exchange energy.
Define orbital?
Calculate the uncertainty in position of an electron, if Δv = 0.1% and υ = 2.2 × 106 ms-1
Determine the values of all the four quantum numbers of the 8th electron in the O-atom and 15th electron in Cl atom.
For each of the following, give the sub level designation, the allowable m values and the number of orbitals
- n = 4, l = 2
- n = 5, l = 3
- n = 7, l = 0
Give the electronic configuration of Mn2+ and Cr3+
An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electrons. Find the symbol of the ion.
