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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

Starting from Hydrogen Gas How Would You Obtain a Basic Gas.

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प्रश्न

Starting from hydrogen gas how would you obtain a basic gas.

एक पंक्ति में उत्तर
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उत्तर

3 volumes of H2 react with 1 vol. of N2 gas in presence of catalyst (finely divided Fe at 450-500°C) and a basic gas ammonia is produced.

\[\ce{\underset{\text{1 vol.}}{N2} +\underset{\text{3 vol.}}{3H2} ⇌[450-500°C][Fe]\underset{\text{(Ammonia gas)}}{2NH3}}\]

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Preparation of Hydrogen
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अध्याय 7: Hydrogen - Exercises

संबंधित प्रश्न

Multiple Choice Question

The metal which reacts with cold water to produce hydrogen is


TRUE \ FALSE

Hydrogen does not combine with nitrogen under ordinary conditions.


MATCH THE COLUMNS

       column A          column  B
1. `""2H_2 + O_2 → 2H_2O` A. This reaction is not         possible 
2. `""H_2+CI_2 →2HCI` B.This reaction is exothermic to the extent of explosion 
3.`""ZaO+ H^2→Zn +H_2O` C.This reaction is known as Haber process 
4.`""Cu + H_2SO^4 → CuSO_4 + H_2 ` D.This reaction illustrates the reducing property of bydrogen 
5.`""N_2 +3H_2 → 2NH_3 +heat ` E. This reaction takes place in diffused sunlight 
  F. This reaction is a method of preparation of hydrogen

 


Why nitric acid is not used in the preparation of hydrogen?


‘Hydrogen is obtained by electrolysis of acidified water’.
Answer the following pertaining to the preparation of hydrogen by electrolysis,
The meaning of the term ‘electrolysis’ and ‘electrolyte’.


Give reason for the following:

In the preparation of hydrogen by electrolysis of water – the distilled water used is acidified.


Select the correct options for the following statement:

The acid _____ is not Used in the laboratory preparation of hydrogen, using zinc and an acid.


Complete and balance the equation:

[General method]

Reactions of active metals - cold water

Calcium - Ca + H2O → ______+ _______ [g]


Select the correct answer to the reactant added, to give the product in the preparation of hydrogen gas.

\[\ce{MgO + H2}\]


Give a balanced equation for the following conversion.

\[\ce{NH3<-H2->H2S}\]


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