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प्रश्न
Starting from (−1) × 5, write various products showing some pattern to show (−1) × (−1) =1.
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उत्तर
−1 × 5 = −5
−1 × 4 = −4 = − 5 + 1
−1 × 3 = −3 = − 4 + 1
−1 × 2 = −2 = − 3 + 1
−1 × 1 = −1 = − 2 + 1
−1 × 0 = 0 = − 1 + 1
Therefore, −1 × (−1) = 0 + 1 = 1
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संबंधित प्रश्न
Replace the blank with an integer to make it a true statement.
_____ × (–12) = 132
_____ × 75 = 0
8 × (−4) = 32
11 × (−1) = ______
Which of the following is the multiplicative identity for an integer a?
______ × (–1) = 47
Match the following:
| Column I | Column II |
| (a) a × 1 | (i) Additive inverse of a |
| (b) 1 | (ii) Additive identity |
| (c) (–a) ÷ (–b) | (iii) Multiplicative identity |
| (d) a × (–1) | (iv) a ÷ (–b) |
| (e) a × 0 | (v) a ÷ b |
| (f) (–a) ÷ b | (vi) a |
| (g) 0 | (vii) –a |
| (h) a ÷ (–a) | (viii) 0 |
| (i) –a | (ix) –1 |
Below u, v, w and x represent different integers, where u = –4 and x ≠ 1. By using following equations, find each of the values:
u × v = u
x × w = w
u + x = w
- v
- w
- x
Explain your reasoning using the properties of integers.
Determine the integer whose product with (–1) is 37.
Determine the integer whose product with (–1) is 0.
