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Solve: x/a - (a + b)/x = (b(a + b))/(ax)

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प्रश्न

Solve:

`x/a - (a + b)/x = (b(a + b))/(ax)`

If x ≠ 0 and a ≠ 0, Solve:

`x/a - (a + b)/x = (b(a + b))/(ax)`

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उत्तर

`x/a - (a + b)/x = (b(a + b))/(ax)`

`(x^2 - a(a + b))/(ax) = ((ab + b^2)/(ax))`

⇒ `(x^2 - a^2 - ab)/(ax) xx ax = ab + b^2`

⇒ x2 – a2 – ab = ab + b2

⇒ x2 = a2 + ab + ab + b2

⇒ x2 = a2 + 2ab + b2

⇒ x2 = (a + b)2

⇒ x2 − (a + b)2 = 0

⇒ x2 = (a + b)(a + b)

⇒ (x − (a + b)) (x + (a + b)) = 0

⇒ x = a + b or x = −(a + b)

⇒ x = ± (a + b)

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अध्याय 5: Quadratic Equations - EXERCISE 5 (B) [पृष्ठ ५४]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic Equations
EXERCISE 5 (B) | Q 14. | पृष्ठ ५४
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