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प्रश्न
Solve for x:
4x2 + 4bx − (a2 − b2) = 0
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उत्तर
The given quadratic equation is.`4x^2+4bx-(a^2-b^2)=0`
`4x^2+2(a+b)x-2(a-b)x-(a^2-b^2)=0`
`2x(2x+a+b)-(a-b)(2x+a+b)=0`
Therefore,
`2x-(a-b)=0`
`2x=a-b`
`x=(a-b)/2`
or
`2x+a+b=0`
`2x=a-b`
`x=(a-b)/2`
or
`2x+a+b=0`
`2x=-(a+b)`
`x=-(a-b)/2`
Thus, the solutions of the given quadratic equation are
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