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Solve the system of equations by using the method of cross multiplication: 6x – 5y – 16 = 0, 7x – 13y + 10 = 0

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प्रश्न

Solve the system of equations by using the method of cross multiplication:

6x – 5y – 16 = 0, 7x – 13y + 10 = 0

Solve the following system of equations by using the method of cross multiplication:

6x – 5y – 16 = 0, 7x – 13y + 10 = 0

योग
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उत्तर

The given equations are:

6x – 5y – 16 = 0   ...(i)

7x – 13y + 10 = 0   ...(ii)

Here a1 = 6, b1 = –5, c1 = –16, a2 = 7, b2 = –13 and c2 = 10

By cross multiplication, we have:

∴ `x/([(-5) xx 10 -(-16) xx (-13)]) = y/([(-16) xx 7 - 10 xx 6]) = 1/([6 xx (-13) - (-5) xx 7])`

⇒ `x/((-50 - 208)) = y/((-112 - 60)) = 1/((-78 + 35))`

⇒ `x/((-258)) = y/((-172)) = 1/((43))`

⇒ `x = (-258)/(-43) = 6, y = (-172)/(-43) = 4`

Hence, x = 6 and y = 4 is the required solution.

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अध्याय 3: Linear Equations in Two Variables - EXERCISE 3C [पृष्ठ ११७]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 3 Linear Equations in Two Variables
EXERCISE 3C | Q 3. | पृष्ठ ११७
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