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प्रश्न
Solve the given quadratic equation by using the formula method:
5x2 + 13x + 8 = 0
योग
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उत्तर
5x2 + 13x + 8 = 0
Comparing with ax2 + bx + c = 0
a = 5, b = 13, c = 8
b2 − 4ac = (13)2 − 4(5)(8)
= 169 − 160
= 9
`x = (-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-13 +- sqrt9)/(2 xx 5)`
= `(-13 +- 3)/10`
∴ x = `(-13 + 3)/10` or x = `(-13 - 3)/10`
∴ x = `(-10)/10` or x = `(-16)/10`
∴ x = −1 or x = `(-8)/5`
∴ Roots are −1 and `(-8)/5`.
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