Advertisements
Advertisements
प्रश्न
Solve the following:
`(y - (4 - 3y))/(2y - (3 + 4y)) = 1/5`
Advertisements
उत्तर
Given, `(y - (4 - 3y))/(2y - (3 + 4y)) = 1/5`
⇒ 5(y – 4 + 3y) = 2y – 3 – 4y ...[By cross-multiplication]
⇒ 5(4y – 4) = – 3 – 2y
⇒ 20y – 20 = – 3 – 2y
⇒ 20y + 2y = 20 – 3 ...[Transposing – 20 to RHS and – 2y to LHS]
⇒ 22y = 17
⇒ `(22y)/22 = 17/22` ...[Dividing both sides by 22]
∴ `y = 17/22`
APPEARS IN
संबंधित प्रश्न
The base of an isosceles triangle is `4/3` cm. The perimeter of the triangle is `4 2/15` cm. What is the length of either of the remaining equal sides?
If 6x = 18, then 18x = 54
Solve the following:
`(0.2x + 5)/(3.5x - 3) = 2/5`
Solve the following:
`x/5 = (x - 1)/6`
Solve the following:
8x – 7 – 3x = 6x – 2x – 3
Solve the following:
`(2x - 1)/5 = (3x + 1)/3`
Solve the following:
`(3t + 5)/4 - 1 = (4t - 3)/5`
Solve the following:
0.25(4x – 5) = 0.75x + 8
Solve the following:
`(3x + 2)/(2x - 3) = - 3/4`
Solve the following:
0.16(5x – 2) = 0.4x + 7
