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प्रश्न
Solve the following simultaneous equations:
x + y = 3; 3x − 2y = 4
योग
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उत्तर
x + y = 3 ...(I)
3x − 2y = 4 ...(II)
Multiply equation (I) by 2, we get
2x + 2y = 6 .......(III)
Add equations (II) and (III), we get
3x − 2y = 4
+ 2x + 2y = 6
5x = 10
∴ x = 2
Put the value of x = 2 in equation (I), we get
x + y = 3
2 + y = 3
y = 3 − 2
y = 1
∴ (x, y) = (2, 1)
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