Advertisements
Advertisements
प्रश्न
Solve the following riddle:
I am a number,
Tell my identity!
Take me seven times over
And add a fifty!
To reach a triple century
You still need forty!
Advertisements
उत्तर
Let the number be x.
(7x + 50) + 40 = 300
7x + 90 = 300
7x = 300 − 90 ...(Transposing 90 to R.H.S.)
7x = 210
Dividing both sides by 7,
`(7x)/7 = 210/7`
x = 30
Therefore, the number is 30.
APPEARS IN
संबंधित प्रश्न
Set up equation and solve them to find the unknown number in the following case:
When I subtracted 11 from twice a number, the result was 15.
People of Sundargram planted trees in the village garden. Some of the trees were fruit trees. The number of non-fruit trees was two more than three times the number of fruit trees. What was the number of fruit trees planted if the number of non-fruit trees planted was 77?
In a test Abha gets twice the marks as that of Palak. Two times Abha's marks and three times Palak's marks make 280.
The solution of the equation is ______.
In a bag there are 5 and 2 rupee coins. If they are equal in number and their worth is ₹ 70, then
The worth of x coins of ₹ 2 each ______.
In a bag there are 5 and 2 rupee coins. If they are equal in number and their worth is ₹ 70, then
The equation formed is ______.
In a Mathematics quiz, 30 prizes consisting of 1st and 2nd prizes only are to be given. 1st and 2nd prizes are worth ₹ 2000 and ₹ 1000, respectively. If the total prize money is ₹ 52,000 then show that:
The equation formed is ______.
One-fifth of a number is 5 less than that number.
A number is 7 more than one-third of itself.
The sum of two consecutive multiples of 2 is 18. Find the numbers.
Twice a number added to half of itself equals 24. Find the number.
