हिंदी

Solve the following quadratic equations by factorization: abx^2 + (b^2 – ac)x – bc = 0

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प्रश्न

Solve the following quadratic equations by factorization:

abx2 + (b2 – ac)x – bc = 0

Using quadratic formula find the value of x.

abx2 + (b2 – ac)x – bc = 0

योग
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उत्तर

We have been given

abx2 + (b2 – ac)x – bc = 0

abx2 + b2x – acx – bc = 0

bx(ax + b) – c(ax + b) = 0

(ax + b)(bx – c) = 0

Therefore,

ax + b = 0

ax = – b

`x = (-b)/a`

or

bx – c = 0

bx = c

`x = c/b`

Hence, `x=(-b)/a` or `x = c/b`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Quadratic Equations - Exercise 5 (E) [पृष्ठ ६६]

APPEARS IN

सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic Equations
Exercise 5 (E) | Q 12.(ii) | पृष्ठ ६६
आर.डी. शर्मा Mathematics [English] Class 10
अध्याय 4 Quadratic Equations
EXERCISE 4.3 | Q 20. | पृष्ठ ४.१६
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